4(2x+1)=8(2x-1)

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Solution for 4(2x+1)=8(2x-1) equation:



4(2x+1)=8(2x-1)
We move all terms to the left:
4(2x+1)-(8(2x-1))=0
We multiply parentheses
8x-(8(2x-1))+4=0
We calculate terms in parentheses: -(8(2x-1)), so:
8(2x-1)
We multiply parentheses
16x-8
Back to the equation:
-(16x-8)
We get rid of parentheses
8x-16x+8+4=0
We add all the numbers together, and all the variables
-8x+12=0
We move all terms containing x to the left, all other terms to the right
-8x=-12
x=-12/-8
x=1+1/2

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