4(2x+1)=6(x-1)+6(x+2)

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Solution for 4(2x+1)=6(x-1)+6(x+2) equation: 



4(2x+1)=6(x-1)+6(x+2)

We move all terms to the left:

4(2x+1)-(6(x-1)+6(x+2))=0

We multiply parentheses

8x-(6(x-1)+6(x+2))+4=0



We calculate terms in parentheses: -(6(x-1)+6(x+2)), so:

6(x-1)+6(x+2)

We multiply parentheses

6x+6x-6+12

We add all the numbers together, and all the variables

12x+6

Back to the equation:

-(12x+6)



We get rid of parentheses

8x-12x-6+4=0

We add all the numbers together, and all the variables

-4x-2=0

We move all terms containing x to the left, all other terms to the right

-4x=2

x=2/-4

x=-1/2

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