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4(2x+1)=3(2x+2)
We move all terms to the left:
4(2x+1)-(3(2x+2))=0
We multiply parentheses
8x-(3(2x+2))+4=0
We calculate terms in parentheses: -(3(2x+2)), so:We get rid of parentheses
3(2x+2)
We multiply parentheses
6x+6
Back to the equation:
-(6x+6)
8x-6x-6+4=0
We add all the numbers together, and all the variables
2x-2=0
We move all terms containing x to the left, all other terms to the right
2x=2
x=2/2
x=1
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