4(2x+1)-3(x-2)=10+5x

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Solution for 4(2x+1)-3(x-2)=10+5x equation: 


Simplifying
4(2x + 1) + -3(x + -2) = 10 + 5x

Reorder the terms:
4(1 + 2x) + -3(x + -2) = 10 + 5x
(1 * 4 + 2x * 4) + -3(x + -2) = 10 + 5x
(4 + 8x) + -3(x + -2) = 10 + 5x

Reorder the terms:
4 + 8x + -3(-2 + x) = 10 + 5x
4 + 8x + (-2 * -3 + x * -3) = 10 + 5x
4 + 8x + (6 + -3x) = 10 + 5x

Reorder the terms:
4 + 6 + 8x + -3x = 10 + 5x

Combine like terms: 4 + 6 = 10
10 + 8x + -3x = 10 + 5x

Combine like terms: 8x + -3x = 5x
10 + 5x = 10 + 5x

Add '-10' to each side of the equation.
10 + -10 + 5x = 10 + -10 + 5x

Combine like terms: 10 + -10 = 0
0 + 5x = 10 + -10 + 5x
5x = 10 + -10 + 5x

Combine like terms: 10 + -10 = 0
5x = 0 + 5x
5x = 5x

Add '-5x' to each side of the equation.
5x + -5x = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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