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4(2x+1)+2(2x+1)=3(x+3)
We move all terms to the left:
4(2x+1)+2(2x+1)-(3(x+3))=0
We multiply parentheses
8x+4x-(3(x+3))+4+2=0
We calculate terms in parentheses: -(3(x+3)), so:We add all the numbers together, and all the variables
3(x+3)
We multiply parentheses
3x+9
Back to the equation:
-(3x+9)
12x-(3x+9)+6=0
We get rid of parentheses
12x-3x-9+6=0
We add all the numbers together, and all the variables
9x-3=0
We move all terms containing x to the left, all other terms to the right
9x=3
x=3/9
x=1/3
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