4(2x+)=29+3(2x-5)

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Solution for 4(2x+)=29+3(2x-5) equation: 



4(2x+)=29+3(2x-5)

We move all terms to the left:

4(2x+)-(29+3(2x-5))=0

We add all the numbers together, and all the variables

4(+2x)-(29+3(2x-5))=0

We multiply parentheses

8x-(29+3(2x-5))=0



We calculate terms in parentheses: -(29+3(2x-5)), so:

29+3(2x-5)

determiningTheFunctionDomain
3(2x-5)+29

We multiply parentheses

6x-15+29

We add all the numbers together, and all the variables

6x+14

Back to the equation:

-(6x+14)



We get rid of parentheses

8x-6x-14=0

We add all the numbers together, and all the variables

2x-14=0

We move all terms containing x to the left, all other terms to the right

2x=14

x=14/2

x=7

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