4(2v-2)-28=2(-v-3)

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Solution for 4(2v-2)-28=2(-v-3) equation: 



4(2v-2)-28=2(-v-3)

We move all terms to the left:

4(2v-2)-28-(2(-v-3))=0

We add all the numbers together, and all the variables

4(2v-2)-(2(-1v-3))-28=0

We multiply parentheses

8v-(2(-1v-3))-8-28=0



We calculate terms in parentheses: -(2(-1v-3)), so:

2(-1v-3)

We multiply parentheses

-2v-6

Back to the equation:

-(-2v-6)



We add all the numbers together, and all the variables

8v-(-2v-6)-36=0

We get rid of parentheses

8v+2v+6-36=0

We add all the numbers together, and all the variables

10v-30=0

We move all terms containing v to the left, all other terms to the right

10v=30

v=30/10

v=3

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