4(2s-3)=3-(s+1)

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Solution for 4(2s-3)=3-(s+1) equation: 



4(2s-3)=3-(s+1)

We move all terms to the left:

4(2s-3)-(3-(s+1))=0

We multiply parentheses

8s-(3-(s+1))-12=0



We calculate terms in parentheses: -(3-(s+1)), so:

3-(s+1)

determiningTheFunctionDomain
-(s+1)+3

We get rid of parentheses

-s-1+3

We add all the numbers together, and all the variables

-1s+2

Back to the equation:

-(-1s+2)



We get rid of parentheses

8s+1s-2-12=0

We add all the numbers together, and all the variables

9s-14=0

We move all terms containing s to the left, all other terms to the right

9s=14

s=14/9

s=1+5/9

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