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4(2s+3)=3(s-1)
We move all terms to the left:
4(2s+3)-(3(s-1))=0
We multiply parentheses
8s-(3(s-1))+12=0
We calculate terms in parentheses: -(3(s-1)), so:We get rid of parentheses
3(s-1)
We multiply parentheses
3s-3
Back to the equation:
-(3s-3)
8s-3s+3+12=0
We add all the numbers together, and all the variables
5s+15=0
We move all terms containing s to the left, all other terms to the right
5s=-15
s=-15/5
s=-3
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