4(2r-8)=7(7r+10)

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Solution for 4(2r-8)=7(7r+10) equation: 



4(2r-8)=7(7r+10)

We move all terms to the left:

4(2r-8)-(7(7r+10))=0

We multiply parentheses

8r-(7(7r+10))-32=0



We calculate terms in parentheses: -(7(7r+10)), so:

7(7r+10)

We multiply parentheses

49r+70

Back to the equation:

-(49r+70)



We get rid of parentheses

8r-49r-70-32=0

We add all the numbers together, and all the variables

-41r-102=0

We move all terms containing r to the left, all other terms to the right

-41r=102

r=102/-41

r=-2+20/41

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