4(2r-8)=1/7(49r+7-)

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Solution for 4(2r-8)=1/7(49r+7-) equation: 



4(2r-8)=1/7(49r+7-)

We move all terms to the left:

4(2r-8)-(1/7(49r+7-))=0



Domain of the equation: 7(49r+7-))!=0

r∈R



We add all the numbers together, and all the variables

4(2r-8)-(1/7(+49r))=0

We multiply parentheses

8r-(1/7(+49r))-32=0

We multiply all the terms by the denominator


8r*7(+49r))-(1-32*7(+49r))=0

Wy multiply elements

56r^2(+-224r(+=0

We use the square of the difference formula

56r^2(-224r(+=0

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