4(2r-6)/8=10

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Solution for 4(2r-6)/8=10 equation: 



4(2r-6)/8=10

We move all terms to the left:

4(2r-6)/8-(10)=0

We multiply all the terms by the denominator


4(2r-6)-10*8=0

We add all the numbers together, and all the variables

4(2r-6)-80=0

We multiply parentheses

8r-24-80=0

We add all the numbers together, and all the variables

8r-104=0

We move all terms containing r to the left, all other terms to the right

8r=104

r=104/8

r=13

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