4(2r+3)=15-11+1-7r

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Solution for 4(2r+3)=15-11+1-7r equation: 



4(2r+3)=15-11+1-7r

We move all terms to the left:

4(2r+3)-(15-11+1-7r)=0

We add all the numbers together, and all the variables

4(2r+3)-(-7r+5)=0

We multiply parentheses

8r-(-7r+5)+12=0

We get rid of parentheses

8r+7r-5+12=0

We add all the numbers together, and all the variables

15r+7=0

We move all terms containing r to the left, all other terms to the right

15r=-7

r=-7/15

r=-7/15

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