4(2n-5)=28

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Solution for 4(2n-5)=28 equation:



4(2n-5)=28
We move all terms to the left:
4(2n-5)-(28)=0
We multiply parentheses
8n-20-28=0
We add all the numbers together, and all the variables
8n-48=0
We move all terms containing n to the left, all other terms to the right
8n=48
n=48/8
n=6

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