4(2n-3)+20=40

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Solution for 4(2n-3)+20=40 equation: 



4(2n-3)+20=40

We move all terms to the left:

4(2n-3)+20-(40)=0

We add all the numbers together, and all the variables

4(2n-3)-20=0

We multiply parentheses

8n-12-20=0

We add all the numbers together, and all the variables

8n-32=0

We move all terms containing n to the left, all other terms to the right

8n=32

n=32/8

n=4

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