4(2n+3)=31-3(n-1)

Solution for 4(2n+3)=31-3(n-1) equation:

4(2n+3)=31-3(n-1)

We move all terms to the left:

4(2n+3)-(31-3(n-1))=0

We multiply parentheses

8n-(31-3(n-1))+12=0


We calculate terms in parentheses: -(31-3(n-1)), so:

31-3(n-1)

determiningTheFunctionDomain
-3(n-1)+31

We multiply parentheses

-3n+3+31

We add all the numbers together, and all the variables

-3n+34

Back to the equation:

-(-3n+34)


We get rid of parentheses

8n+3n-34+12=0

We add all the numbers together, and all the variables

11n-22=0

We move all terms containing n to the left, all other terms to the right

11n=22

n=22/11

n=2