4(2n+1)=7(6n+4)+9

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Solution for 4(2n+1)=7(6n+4)+9 equation: 



4(2n+1)=7(6n+4)+9

We move all terms to the left:

4(2n+1)-(7(6n+4)+9)=0

We multiply parentheses

8n-(7(6n+4)+9)+4=0



We calculate terms in parentheses: -(7(6n+4)+9), so:

7(6n+4)+9

We multiply parentheses

42n+28+9

We add all the numbers together, and all the variables

42n+37

Back to the equation:

-(42n+37)



We get rid of parentheses

8n-42n-37+4=0

We add all the numbers together, and all the variables

-34n-33=0

We move all terms containing n to the left, all other terms to the right

-34n=33

n=33/-34

n=-33/34

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