4(2n+1)=7(6n+2)+7

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Solution for 4(2n+1)=7(6n+2)+7 equation: 



4(2n+1)=7(6n+2)+7

We move all terms to the left:

4(2n+1)-(7(6n+2)+7)=0

We multiply parentheses

8n-(7(6n+2)+7)+4=0



We calculate terms in parentheses: -(7(6n+2)+7), so:

7(6n+2)+7

We multiply parentheses

42n+14+7

We add all the numbers together, and all the variables

42n+21

Back to the equation:

-(42n+21)



We get rid of parentheses

8n-42n-21+4=0

We add all the numbers together, and all the variables

-34n-17=0

We move all terms containing n to the left, all other terms to the right

-34n=17

n=17/-34

n=-1/2

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