4(2m+1)=2(m-13)

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Solution for 4(2m+1)=2(m-13) equation: 



4(2m+1)=2(m-13)

We move all terms to the left:

4(2m+1)-(2(m-13))=0

We multiply parentheses

8m-(2(m-13))+4=0



We calculate terms in parentheses: -(2(m-13)), so:

2(m-13)

We multiply parentheses

2m-26

Back to the equation:

-(2m-26)



We get rid of parentheses

8m-2m+26+4=0

We add all the numbers together, and all the variables

6m+30=0

We move all terms containing m to the left, all other terms to the right

6m=-30

m=-30/6

m=-5

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