4(2k-6)=3(2k+3)

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Solution for 4(2k-6)=3(2k+3) equation: 



4(2k-6)=3(2k+3)

We move all terms to the left:

4(2k-6)-(3(2k+3))=0

We multiply parentheses

8k-(3(2k+3))-24=0



We calculate terms in parentheses: -(3(2k+3)), so:

3(2k+3)

We multiply parentheses

6k+9

Back to the equation:

-(6k+9)



We get rid of parentheses

8k-6k-9-24=0

We add all the numbers together, and all the variables

2k-33=0

We move all terms containing k to the left, all other terms to the right

2k=33

k=33/2

k=16+1/2

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