4(2k-5)=2(-k+5)

Solution for 4(2k-5)=2(-k+5) equation:

4(2k-5)=2(-k+5)

We move all terms to the left:

4(2k-5)-(2(-k+5))=0

We add all the numbers together, and all the variables

4(2k-5)-(2(-1k+5))=0

We multiply parentheses

8k-(2(-1k+5))-20=0


We calculate terms in parentheses: -(2(-1k+5)), so:

2(-1k+5)

We multiply parentheses

-2k+10

Back to the equation:

-(-2k+10)


We get rid of parentheses

8k+2k-10-20=0

We add all the numbers together, and all the variables

10k-30=0

We move all terms containing k to the left, all other terms to the right

10k=30

k=30/10

k=3