4(2k-3)=6(k-2)+2k

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Solution for 4(2k-3)=6(k-2)+2k equation: 



4(2k-3)=6(k-2)+2k

We move all terms to the left:

4(2k-3)-(6(k-2)+2k)=0

We multiply parentheses

8k-(6(k-2)+2k)-12=0



We calculate terms in parentheses: -(6(k-2)+2k), so:

6(k-2)+2k

We add all the numbers together, and all the variables

2k+6(k-2)

We multiply parentheses

2k+6k-12

We add all the numbers together, and all the variables

8k-12

Back to the equation:

-(8k-12)



We get rid of parentheses

8k-8k+12-12=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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