4(2k-3)=28

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Solution for 4(2k-3)=28 equation: 



4(2k-3)=28

We move all terms to the left:

4(2k-3)-(28)=0

We multiply parentheses

8k-12-28=0

We add all the numbers together, and all the variables

8k-40=0

We move all terms containing k to the left, all other terms to the right

8k=40

k=40/8

k=5

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