4(2k-3)+1=(8k-11)

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Solution for 4(2k-3)+1=(8k-11) equation: 



4(2k-3)+1=(8k-11)

We move all terms to the left:

4(2k-3)+1-((8k-11))=0

We multiply parentheses

8k-((8k-11))-12+1=0



We calculate terms in parentheses: -((8k-11)), so:

(8k-11)

We get rid of parentheses

8k-11

Back to the equation:

-(8k-11)



We add all the numbers together, and all the variables

8k-(8k-11)-11=0

We get rid of parentheses

8k-8k+11-11=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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