4(2h+1)=27-3(-2h+5)

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Solution for 4(2h+1)=27-3(-2h+5) equation:



4(2h+1)=27-3(-2h+5)
We move all terms to the left:
4(2h+1)-(27-3(-2h+5))=0
We multiply parentheses
8h-(27-3(-2h+5))+4=0
We calculate terms in parentheses: -(27-3(-2h+5)), so:
27-3(-2h+5)
determiningTheFunctionDomain -3(-2h+5)+27
We multiply parentheses
6h-15+27
We add all the numbers together, and all the variables
6h+12
Back to the equation:
-(6h+12)
We get rid of parentheses
8h-6h-12+4=0
We add all the numbers together, and all the variables
2h-8=0
We move all terms containing h to the left, all other terms to the right
2h=8
h=8/2
h=4

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