4(2g+3)=-3(g-1)+31

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Solution for 4(2g+3)=-3(g-1)+31 equation: 



4(2g+3)=-3(g-1)+31

We move all terms to the left:

4(2g+3)-(-3(g-1)+31)=0

We multiply parentheses

8g-(-3(g-1)+31)+12=0



We calculate terms in parentheses: -(-3(g-1)+31), so:

-3(g-1)+31

We multiply parentheses

-3g+3+31

We add all the numbers together, and all the variables

-3g+34

Back to the equation:

-(-3g+34)



We get rid of parentheses

8g+3g-34+12=0

We add all the numbers together, and all the variables

11g-22=0

We move all terms containing g to the left, all other terms to the right

11g=22

g=22/11

g=2

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