4(2d-7)=19d-6

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Solution for 4(2d-7)=19d-6 equation: 



4(2d-7)=19d-6

We move all terms to the left:

4(2d-7)-(19d-6)=0

We multiply parentheses

8d-(19d-6)-28=0

We get rid of parentheses

8d-19d+6-28=0

We add all the numbers together, and all the variables

-11d-22=0

We move all terms containing d to the left, all other terms to the right

-11d=22

d=22/-11

d=-2

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