4(2d-4)+3=3(d+1)+4

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Solution for 4(2d-4)+3=3(d+1)+4 equation: 



4(2d-4)+3=3(d+1)+4

We move all terms to the left:

4(2d-4)+3-(3(d+1)+4)=0

We multiply parentheses

8d-(3(d+1)+4)-16+3=0



We calculate terms in parentheses: -(3(d+1)+4), so:

3(d+1)+4

We multiply parentheses

3d+3+4

We add all the numbers together, and all the variables

3d+7

Back to the equation:

-(3d+7)



We add all the numbers together, and all the variables

8d-(3d+7)-13=0

We get rid of parentheses

8d-3d-7-13=0

We add all the numbers together, and all the variables

5d-20=0

We move all terms containing d to the left, all other terms to the right

5d=20

d=20/5

d=4

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