4(2c-5)+3c=57

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Solution for 4(2c-5)+3c=57 equation: 



4(2c-5)+3c=57

We move all terms to the left:

4(2c-5)+3c-(57)=0

We add all the numbers together, and all the variables

3c+4(2c-5)-57=0

We multiply parentheses

3c+8c-20-57=0

We add all the numbers together, and all the variables

11c-77=0

We move all terms containing c to the left, all other terms to the right

11c=77

c=77/11

c=7

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