4(2c-1)-4=5c+5

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Solution for 4(2c-1)-4=5c+5 equation: 



4(2c-1)-4=5c+5

We move all terms to the left:

4(2c-1)-4-(5c+5)=0

We multiply parentheses

8c-(5c+5)-4-4=0

We get rid of parentheses

8c-5c-5-4-4=0

We add all the numbers together, and all the variables

3c-13=0

We move all terms containing c to the left, all other terms to the right

3c=13

c=13/3

c=4+1/3

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