4(2c+3)=-3(c-1)+31

Solution for 4(2c+3)=-3(c-1)+31 equation:

4(2c+3)=-3(c-1)+31

We move all terms to the left:

4(2c+3)-(-3(c-1)+31)=0

We multiply parentheses

8c-(-3(c-1)+31)+12=0


We calculate terms in parentheses: -(-3(c-1)+31), so:

-3(c-1)+31

We multiply parentheses

-3c+3+31

We add all the numbers together, and all the variables

-3c+34

Back to the equation:

-(-3c+34)


We get rid of parentheses

8c+3c-34+12=0

We add all the numbers together, and all the variables

11c-22=0

We move all terms containing c to the left, all other terms to the right

11c=22

c=22/11

c=2