4(2c+1)=5(c-1)

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Solution for 4(2c+1)=5(c-1) equation:


Simplifying
4(2c + 1) = 5(c + -1)

Reorder the terms:
4(1 + 2c) = 5(c + -1)
(1 * 4 + 2c * 4) = 5(c + -1)
(4 + 8c) = 5(c + -1)

Reorder the terms:
4 + 8c = 5(-1 + c)
4 + 8c = (-1 * 5 + c * 5)
4 + 8c = (-5 + 5c)

Solving
4 + 8c = -5 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
4 + 8c + -5c = -5 + 5c + -5c

Combine like terms: 8c + -5c = 3c
4 + 3c = -5 + 5c + -5c

Combine like terms: 5c + -5c = 0
4 + 3c = -5 + 0
4 + 3c = -5

Add '-4' to each side of the equation.
4 + -4 + 3c = -5 + -4

Combine like terms: 4 + -4 = 0
0 + 3c = -5 + -4
3c = -5 + -4

Combine like terms: -5 + -4 = -9
3c = -9

Divide each side by '3'.
c = -3

Simplifying
c = -3

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