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4(2c+1)-3=6c+3
We move all terms to the left:
4(2c+1)-3-(6c+3)=0
We multiply parentheses
8c-(6c+3)+4-3=0
We get rid of parentheses
8c-6c-3+4-3=0
We add all the numbers together, and all the variables
2c-2=0
We move all terms containing c to the left, all other terms to the right
2c=2
c=2/2
c=1
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