4(2b-3)=7(b+1)

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Solution for 4(2b-3)=7(b+1) equation: 



4(2b-3)=7(b+1)

We move all terms to the left:

4(2b-3)-(7(b+1))=0

We multiply parentheses

8b-(7(b+1))-12=0



We calculate terms in parentheses: -(7(b+1)), so:

7(b+1)

We multiply parentheses

7b+7

Back to the equation:

-(7b+7)



We get rid of parentheses

8b-7b-7-12=0

We add all the numbers together, and all the variables

b-19=0

We move all terms containing b to the left, all other terms to the right

b=19

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