4(2b+3)-3(3b-2)=7

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Solution for 4(2b+3)-3(3b-2)=7 equation: 



4(2b+3)-3(3b-2)=7

We move all terms to the left:

4(2b+3)-3(3b-2)-(7)=0

We multiply parentheses

8b-9b+12+6-7=0

We add all the numbers together, and all the variables

-1b+11=0

We move all terms containing b to the left, all other terms to the right

-b=-11

b=-11/-1

b=+11

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