4(2a+3)-7=3(a-5)

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Solution for 4(2a+3)-7=3(a-5) equation: 



4(2a+3)-7=3(a-5)

We move all terms to the left:

4(2a+3)-7-(3(a-5))=0

We multiply parentheses

8a-(3(a-5))+12-7=0



We calculate terms in parentheses: -(3(a-5)), so:

3(a-5)

We multiply parentheses

3a-15

Back to the equation:

-(3a-15)



We add all the numbers together, and all the variables

8a-(3a-15)+5=0

We get rid of parentheses

8a-3a+15+5=0

We add all the numbers together, and all the variables

5a+20=0

We move all terms containing a to the left, all other terms to the right

5a=-20

a=-20/5

a=-4

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