4(2-x)-(x+2)=6+5(x-4)

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Solution for 4(2-x)-(x+2)=6+5(x-4) equation: 



4(2-x)-(x+2)=6+5(x-4)

We move all terms to the left:

4(2-x)-(x+2)-(6+5(x-4))=0

We add all the numbers together, and all the variables

4(-1x+2)-(x+2)-(6+5(x-4))=0

We multiply parentheses

-4x-(x+2)-(6+5(x-4))+8=0

We get rid of parentheses

-4x-x-(6+5(x-4))-2+8=0



We calculate terms in parentheses: -(6+5(x-4)), so:

6+5(x-4)

determiningTheFunctionDomain
5(x-4)+6

We multiply parentheses

5x-20+6

We add all the numbers together, and all the variables

5x-14

Back to the equation:

-(5x-14)



We add all the numbers together, and all the variables

-5x-(5x-14)+6=0

We get rid of parentheses

-5x-5x+14+6=0

We add all the numbers together, and all the variables

-10x+20=0

We move all terms containing x to the left, all other terms to the right

-10x=-20

x=-20/-10

x=+2

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