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4(2-x)+2(1-5x)=5(2-3x)x
We move all terms to the left:
4(2-x)+2(1-5x)-(5(2-3x)x)=0
We add all the numbers together, and all the variables
4(-1x+2)+2(-5x+1)-(5(-3x+2)x)=0
We multiply parentheses
-4x-10x-(5(-3x+2)x)+8+2=0
We calculate terms in parentheses: -(5(-3x+2)x), so:We add all the numbers together, and all the variables
5(-3x+2)x
We multiply parentheses
-15x^2+10x
Back to the equation:
-(-15x^2+10x)
-(-15x^2+10x)-14x+10=0
We get rid of parentheses
15x^2-10x-14x+10=0
We add all the numbers together, and all the variables
15x^2-24x+10=0
a = 15; b = -24; c = +10;
Δ = b2-4ac
Δ = -242-4·15·10
Δ = -24
Delta is less than zero, so there is no solution for the equation
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