4(2-x)+1=2x+2-5(2-4x)

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Solution for 4(2-x)+1=2x+2-5(2-4x) equation: 



4(2-x)+1=2x+2-5(2-4x)

We move all terms to the left:

4(2-x)+1-(2x+2-5(2-4x))=0

We add all the numbers together, and all the variables

4(-1x+2)-(2x+2-5(-4x+2))+1=0

We multiply parentheses

-4x-(2x+2-5(-4x+2))+8+1=0



We calculate terms in parentheses: -(2x+2-5(-4x+2)), so:

2x+2-5(-4x+2)

determiningTheFunctionDomain
2x-5(-4x+2)+2

We multiply parentheses

2x+20x-10+2

We add all the numbers together, and all the variables

22x-8

Back to the equation:

-(22x-8)



We add all the numbers together, and all the variables

-4x-(22x-8)+9=0

We get rid of parentheses

-4x-22x+8+9=0

We add all the numbers together, and all the variables

-26x+17=0

We move all terms containing x to the left, all other terms to the right

-26x=-17

x=-17/-26

x=17/26

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