4(2-q)=2(q-2)

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Solution for 4(2-q)=2(q-2) equation: 



4(2-q)=2(q-2)

We move all terms to the left:

4(2-q)-(2(q-2))=0

We add all the numbers together, and all the variables

4(-1q+2)-(2(q-2))=0

We multiply parentheses

-4q-(2(q-2))+8=0



We calculate terms in parentheses: -(2(q-2)), so:

2(q-2)

We multiply parentheses

2q-4

Back to the equation:

-(2q-4)



We get rid of parentheses

-4q-2q+4+8=0

We add all the numbers together, and all the variables

-6q+12=0

We move all terms containing q to the left, all other terms to the right

-6q=-12

q=-12/-6

q=+2

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