4(2-5)=-2(3s-1)

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Solution for 4(2-5)=-2(3s-1) equation: 



4(2-5)=-2(3s-1)

We move all terms to the left:

4(2-5)-(-2(3s-1))=0

We add all the numbers together, and all the variables

-(-2(3s-1))+4(-3)=0

We add all the numbers together, and all the variables

-(-2(3s-1))-12=0



We calculate terms in parentheses: -(-2(3s-1)), so:

-2(3s-1)

We multiply parentheses

-6s+2

Back to the equation:

-(-6s+2)



We get rid of parentheses

6s-2-12=0

We add all the numbers together, and all the variables

6s-14=0

We move all terms containing s to the left, all other terms to the right

6s=14

s=14/6

s=2+1/3

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