4(2-3-3c-3+2+2c+2)=-2c

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Solution for 4(2-3-3c-3+2+2c+2)=-2c equation: 



4(2-3-3c-3+2+2c+2)=-2c

We move all terms to the left:

4(2-3-3c-3+2+2c+2)-(-2c)=0

We add all the numbers together, and all the variables

4(-1c)-(-2c)=0

We multiply parentheses

-4c-(-2c)=0

We get rid of parentheses

-4c+2c=0

We add all the numbers together, and all the variables

-2c=0

c=0/-2

c=0

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