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4(2-2x)=2(x+1)
We move all terms to the left:
4(2-2x)-(2(x+1))=0
We add all the numbers together, and all the variables
4(-2x+2)-(2(x+1))=0
We multiply parentheses
-8x-(2(x+1))+8=0
We calculate terms in parentheses: -(2(x+1)), so:We get rid of parentheses
2(x+1)
We multiply parentheses
2x+2
Back to the equation:
-(2x+2)
-8x-2x-2+8=0
We add all the numbers together, and all the variables
-10x+6=0
We move all terms containing x to the left, all other terms to the right
-10x=-6
x=-6/-10
x=3/5
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