4(2-(3(c+1)-2(c+1)))=-2c

Solution for 4(2-(3(c+1)-2(c+1)))=-2c equation:

Simplifying
4(2 + -1(3(c + 1) + -2(c + 1))) = -2c

Reorder the terms:
4(2 + -1(3(1 + c) + -2(c + 1))) = -2c
4(2 + -1((1 * 3 + c * 3) + -2(c + 1))) = -2c
4(2 + -1((3 + 3c) + -2(c + 1))) = -2c

Reorder the terms:
4(2 + -1(3 + 3c + -2(1 + c))) = -2c
4(2 + -1(3 + 3c + (1 * -2 + c * -2))) = -2c
4(2 + -1(3 + 3c + (-2 + -2c))) = -2c

Reorder the terms:
4(2 + -1(3 + -2 + 3c + -2c)) = -2c

Combine like terms: 3 + -2 = 1
4(2 + -1(1 + 3c + -2c)) = -2c

Combine like terms: 3c + -2c = 1c
4(2 + -1(1 + 1c)) = -2c
4(2 + (1 * -1 + 1c * -1)) = -2c
4(2 + (-1 + -1c)) = -2c

Combine like terms: 2 + -1 = 1
4(1 + -1c) = -2c
(1 * 4 + -1c * 4) = -2c
(4 + -4c) = -2c

Solving
4 + -4c = -2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '2c' to each side of the equation.
4 + -4c + 2c = -2c + 2c

Combine like terms: -4c + 2c = -2c
4 + -2c = -2c + 2c

Combine like terms: -2c + 2c = 0
4 + -2c = 0

Add '-4' to each side of the equation.
4 + -4 + -2c = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -2c = 0 + -4
-2c = 0 + -4

Combine like terms: 0 + -4 = -4
-2c = -4

Divide each side by '-2'.
c = 2

Simplifying
c = 2