4(2+x+1)=27+3(x-5)

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Solution for 4(2+x+1)=27+3(x-5) equation:


Simplifying
4(2 + x + 1) = 27 + 3(x + -5)

Reorder the terms:
4(2 + 1 + x) = 27 + 3(x + -5)

Combine like terms: 2 + 1 = 3
4(3 + x) = 27 + 3(x + -5)
(3 * 4 + x * 4) = 27 + 3(x + -5)
(12 + 4x) = 27 + 3(x + -5)

Reorder the terms:
12 + 4x = 27 + 3(-5 + x)
12 + 4x = 27 + (-5 * 3 + x * 3)
12 + 4x = 27 + (-15 + 3x)

Combine like terms: 27 + -15 = 12
12 + 4x = 12 + 3x

Add '-12' to each side of the equation.
12 + -12 + 4x = 12 + -12 + 3x

Combine like terms: 12 + -12 = 0
0 + 4x = 12 + -12 + 3x
4x = 12 + -12 + 3x

Combine like terms: 12 + -12 = 0
4x = 0 + 3x
4x = 3x

Solving
4x = 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.
4x + -3x = 3x + -3x

Combine like terms: 4x + -3x = 1x
1x = 3x + -3x

Combine like terms: 3x + -3x = 0
1x = 0

Divide each side by '1'.
x = 0

Simplifying
x = 0

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