4(2+v)-v=6+2(v+1)

Solution for 4(2+v)-v=6+2(v+1) equation:

4(2+v)-v=6+2(v+1)

We move all terms to the left:

4(2+v)-v-(6+2(v+1))=0

We add all the numbers together, and all the variables

4(v+2)-v-(6+2(v+1))=0

We add all the numbers together, and all the variables

-1v+4(v+2)-(6+2(v+1))=0

We multiply parentheses

-1v+4v-(6+2(v+1))+8=0


We calculate terms in parentheses: -(6+2(v+1)), so:

6+2(v+1)

determiningTheFunctionDomain
2(v+1)+6

We multiply parentheses

2v+2+6

We add all the numbers together, and all the variables

2v+8

Back to the equation:

-(2v+8)


We add all the numbers together, and all the variables

3v-(2v+8)+8=0

We get rid of parentheses

3v-2v-8+8=0

We add all the numbers together, and all the variables

v=0