4(2+n)=4(4+2n)

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Solution for 4(2+n)=4(4+2n) equation: 



4(2+n)=4(4+2n)

We move all terms to the left:

4(2+n)-(4(4+2n))=0

We add all the numbers together, and all the variables

4(n+2)-(4(2n+4))=0

We multiply parentheses

4n-(4(2n+4))+8=0



We calculate terms in parentheses: -(4(2n+4)), so:

4(2n+4)

We multiply parentheses

8n+16

Back to the equation:

-(8n+16)



We get rid of parentheses

4n-8n-16+8=0

We add all the numbers together, and all the variables

-4n-8=0

We move all terms containing n to the left, all other terms to the right

-4n=8

n=8/-4

n=-2

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