4(2+k)=3(1+k)

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Solution for 4(2+k)=3(1+k) equation: 



4(2+k)=3(1+k)

We move all terms to the left:

4(2+k)-(3(1+k))=0

We add all the numbers together, and all the variables

4(k+2)-(3(k+1))=0

We multiply parentheses

4k-(3(k+1))+8=0



We calculate terms in parentheses: -(3(k+1)), so:

3(k+1)

We multiply parentheses

3k+3

Back to the equation:

-(3k+3)



We get rid of parentheses

4k-3k-3+8=0

We add all the numbers together, and all the variables

k+5=0

We move all terms containing k to the left, all other terms to the right

k=-5

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