4(2+3x)+6(3x-2)=146

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Solution for 4(2+3x)+6(3x-2)=146 equation: 



4(2+3x)+6(3x-2)=146

We move all terms to the left:

4(2+3x)+6(3x-2)-(146)=0

We add all the numbers together, and all the variables

4(3x+2)+6(3x-2)-146=0

We multiply parentheses

12x+18x+8-12-146=0

We add all the numbers together, and all the variables

30x-150=0

We move all terms containing x to the left, all other terms to the right

30x=150

x=150/30

x=5

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