4(2+2y)+6(y+2)=48

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Solution for 4(2+2y)+6(y+2)=48 equation: 



4(2+2y)+6(y+2)=48

We move all terms to the left:

4(2+2y)+6(y+2)-(48)=0

We add all the numbers together, and all the variables

4(2y+2)+6(y+2)-48=0

We multiply parentheses

8y+6y+8+12-48=0

We add all the numbers together, and all the variables

14y-28=0

We move all terms containing y to the left, all other terms to the right

14y=28

y=28/14

y=2

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